Chewie
BCCI President
let d be the initial distance. the speed of sound initially is 2d/x.
Next he is d-a from the cliff. The speed of sound is 2(d-a)/y
Rearranging for d gives xv/2=d and yv/2+a=d
Equating these gives xv/2=yv/2+a
Multiplying through by 2 gives xv=yv+2a
Rearranging gives v(x-y)=2a
Dividing through by (x-y) gives v=2a/(x-y) which is the answer
Next he is d-a from the cliff. The speed of sound is 2(d-a)/y
Rearranging for d gives xv/2=d and yv/2+a=d
Equating these gives xv/2=yv/2+a
Multiplying through by 2 gives xv=yv+2a
Rearranging gives v(x-y)=2a
Dividing through by (x-y) gives v=2a/(x-y) which is the answer