Brain teasers and challenges.

Nah. I don't really understand how it works. But this is the solution.

The gradient of the teal hypotenuse is different than the gradient of the red hypotenuse

Triangle-Answer.gif
 
Basically when you are rearrange the pieces, the two blocks forming the hypotenuse are not in a straight line, the lower one is slightly bent. Or more technically, the base angles of the two right triangles are not equal. This 'bend' is sufficient enough to create the empty space.

So yes, an illusion.
 
Try your best logic and figure it out. If none of you get the answer by one/two days of this post then I'll reveal it, and I'm sure you'll be amazed if you didn't know the answer already.

By the way please don't be like 1?2?3?4? You should add logic you tried out if you're sure enough that your answer is correct. :)
logic.jpg
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Last time, when I did bring this thread I really had too simple puzzles that were proved out even simpler and dumb than that. I've collected more but bit difficult challenges in a span this time around. Hope y'll will enjoy.
 
Try your best logic and figure it out. If none of you get the answer by one/two days of this post then I'll reveal it, and I'm sure you'll be amazed if you didn't know the answer already.

By the way please don't be like 1?2?3?4? You should add logic you tried out if you're sure enough that your answer is correct. :)
logic-jpg.138249

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Last time, when I did bring this thread I really had too simple puzzles that were proved out even simpler and dumb than that. I've collected more but bit difficult challenges in a span this time around. Hope y'll will enjoy.

Is the answer '0' ?
 
Is the answer '0' ?
So what logic based upon? That what matters.

The particular number and logic will be considered as answer. You guys shouldn't play like 1?2?3? not, then 4? :p

You are close to the answer anyways. :)
 
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The answer is 0.
Logic:
Counting the number of "circles" formed by the digits.
1. 8888 = 8
8 has 2 circles, hence 8888 has 8 circles
2. 9172 = 1
9 has 1 circle, rest have none.
3. 7650 = 2
6 has 1 circle, 0 has 1 circle, rest have none.
4. 2084 = 3
0 has 1 circle, 8 has 2, rest have none
5. 7127 = 0
none of the digits have a circle.
 
The answer is 0.
Logic:
Counting the number of "circles" formed by the digits.
1. 8888 = 8
8 has 2 circles, hence 8888 has 8 circles
2. 9172 = 1
9 has 1 circle, rest have none.
3. 7650 = 2
6 has 1 circle, 0 has 1 circle, rest have none.
4. 2084 = 3
0 has 1 circle, 8 has 2, rest have none
5. 7127 = 0
none of the digits have a circle.

Hell yeah! Not exactly the circles, but the round shapes/figure will do suit. Your answer have been perfect.:clap
 
The answer is 0.
Logic:
Counting the number of "circles" formed by the digits.
1. 8888 = 8
8 has 2 circles, hence 8888 has 8 circles
2. 9172 = 1
9 has 1 circle, rest have none.
3. 7650 = 2
6 has 1 circle, 0 has 1 circle, rest have none.
4. 2084 = 3
0 has 1 circle, 8 has 2, rest have none
5. 7127 = 0
none of the digits have a circle.
Yeah.. that's the same logic I used.
 
False advertising, that answer wasn't remotely obvious.
That's called just advertising.;) The major mistake people do resolving that they think it's algebra which actually not, but is another side of math.
 
Diff: Medium
Can you show that four added to six will make eleven?

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Diff: Easy
How John could find the honest and liar?
path.jpg
 
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Ask one person: "If I were to ask the other person which path was correct what would he say?" and then take the opposite path.

He basically doesn't know who lie and who don't. What if he asks that question to the liar, he/she would suggest exactly the correct path in reply but John still doesn't know that he's talking to liar and take the opposite path which would prove out a wrong one.

He has to find out both liar and honest. Obviously if he finds honest then the other one is liar or find liar first to know who is honest.
 
Last edited:
Diff: Medium
Can you show that four added to six will make eleven?


Firstly, I will prove that 1 = 2
and then prove that four added to six will make eleven... [a2 and b2 means a square and b square respectively]

  1. Let a = b
  2. a2 = ab (Multiplying both sides by a)
  3. a2 - b2 = ab - b2 (Subtract b2 from both sides to get)
  4. So, this implies that (a + b)(a - b) = b(a - b)
  5. a + b = b (Since (a - b) appears on both sides, we can cancel)
  6. b + b = b (Since a = b)
  7. 2b = b
  8. So we get that, 2 = 1 or 1 = 2 (cancelling b on both sides)


Now, add '9' on both sides
This gives us, 10 = 11
6 + 4 = 11 (10 can be broken into 6 + 4)
Hence Proved....
 

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