Homework

[-D-S-B-]

I guess this means detention :crying

 

[Gilly Fan]

Algebraic Fractions. How the fearsome tweak do you multiply them?

 

[drainpipe32]

Multiply the numerators and the denominators?

 

[Gilly Fan]

Try do that with this.

x^2-9........3x+6.......x
-------..X.---------../----
x+2............x-3..........9

 

[Covvy]

I never really get homework. Ah the wonders of a public school!

 

[Gilly Fan]

Ahh the wonders of VCE...

 

[drainpipe32]

Use a Cas?

 

[Cricketman]

Try do that with this.

x^2-9........3x+6.......x
-------..X.---------../----
x+2............x-3..........9

division is nothing but flipping and multiplying...
(x^2) - 9 blahblahblah 27x + 54
---------- x bahblahblah-------- = just multiply straight through....
x+2 blahblahblah (x^2) - 3x

Cricketman added 1 Minutes and 13 Seconds later...

the formatting sucks but you get the idea

 

[drainpipe32]

Without using a Cas I had

27x^3-486
__________
x^3-6

And then divide that.

Or am I an idiot?

 

[Insomniac]

Wtf u and Cricketman have both lost it.

(x^2-9) X (3x+6) = 3x^3 + 6x^2 + (-27x) - 54

And then (x+2) x (x-3) = x^2 - x - 6

So [ 3x^3 + 6x^2 + (-27x) - 54 ] / [ x^2 - x - 6 ] X (9/x) - You flip when dividing

Then,

[ 27x^3 + 54x^2 + (-243x) - 486 ] / [ x^3 - x^2 - 6x]

Easy as 3.14.

Gazza was somehwat close, but thats the full thing. What you have Gazza (its not right, but if it was) cannot be dividing because 6 does not go into 486 27 times - you would've been factoring a 27 out (which isn't possible)

 

[drainpipe32]

Yeah, the fact that 6 wasn't a multiple of 486 threw me off too.

I swear this is exactly like that test I had today

 

[Insomniac]

What kind of education system do you guys have in Australia?

I swear I did this in like grade 1.

 

[drainpipe32]

It obviously doesn't reflect in the ability of your cricket team.

 

[Gilly Fan]

Try again guys. The answer in the book says

1
__ - x(x+3)
x

and yeah, I have nfi how to use my Cas as I only just got it a couple of weeks ago.

 

[Insomniac]

Try again guys. The answer in the book says

1
__ - x(x+3)
x

and yeah, I have nfi how to use my Cas as I only just got it a couple of weeks ago.

The book can eff off.

I did it right _|_

Insomniac added 5 Minutes and 7 Seconds later...

Actually, I'm gonna try to simplify this:

[ 27 (x^3 + 2x^2 - 9x - 18) ] / [ x (x^2 - x - 6) ]

Now, lets work from there.